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Q. A mixture of ethyl alcohol and propyl alcohol has a vapour pressure of $290\, mm$ at $300\, K$. The vapour pressure of propyl alcohol is $200\, mm$. If the mole fraction of ethyl alcohol is $0.6$, its vapour pressure (in mm) at the same temperature will be

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Solution:

Let the vapour pressure of pure ethyl alcohol be P, According to Raoult’s law
$P=\frac{290-80}{0.6}=350\,mm\,Hg$