Question

A mixture of boron trichloride and hydrogen is subjected to silent electric discharge to form A and $\text{HCl}\text{.}$ A is mixed with $\text{N}{\text{H}}_{\text{3}}$ and heated to $\text{200}{}^{\text{o}}\text{C}$ to form B. The formula of B is

• A. ${\text{H}}_{\text{3}}\text{B}{\text{O}}_{\text{3}}$
• B. ${\text{B}}_{\text{2}}{\text{O}}_{\text{3}}$
• C. ${\text{B}}_{\text{3}}{\text{N}}_{\text{3}}{\text{H}}_{\text{6}}$
• D. ${\text{B}}_{\text{2}}{\text{H}}_{\text{6}}$

Answer 1

Answer: (C)

When a mixture of $\text{BC}{\text{l}}_{\text{3}}$ and ${\text{H}}_2$ is subjected to silent electric discharge, diborane and $\text{HCl}$ are formed and diborane reacts with NH3 at $200{}^{o}C$ to give borazine (inorganic benzene). $2BC{l}_3+6H_2\underset{\text{discharge}}{\overset{\text{Electric}}{\to }}\underset{(A)}{B_2{H}_6}+6HCl$ $\underset{1:}{3B_2{H}_6}+\underset{2}{6N{H}_3}\stackrel{200{}^{o}C}{\to }\underset{\begin{array}{c}\text{Borazine}\\ (B)\end{array}}{2B_3{N}_3{H}_6}+12H_2$