A milli voltmeter of 25 milli volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be

Question

A milli voltmeter of 25 milli volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be (A) 0.001 (B) 0.01 (C) 1 (D) 0.05

Tardigrade Admin · Accepted Answer

S=(Vg/(I-Ig)) Neglecting Ig ∴ S=(Vg/I)=(25 × 10-3 V /25 A ) =0.001 Ω

Q. A milli voltmeter of $25$ milli volt range is to be converted into an ammeter of $25$ ampere range. The value (in ohm) of necessary shunt will be

0.001

0.01

1

0.05

$S = \frac{V _{g}}{( I - I _{g} )}$
Neglecting $I_{g}$
$∴ S = \frac{V _{g}}{I} = \frac{25 \times 1 0 ^{- 3} V}{25 A}$
$= 0.001 Ω$

Q. A milli voltmeter of 25 milli volt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be

0.001

0.01

1

0.05

S=(I−Ig​)Vg​​ Neglecting Ig​ ∴S=IVg​​=25A25×10−3V​ =0.001Ω

Q. A milli voltmeter of $25$ milli volt range is to be converted into an ammeter of $25$ ampere range. The value (in ohm) of necessary shunt will be

$S = \frac{V _{g}}{( I - I _{g} )}$
Neglecting $I_{g}$
$∴ S = \frac{V _{g}}{I} = \frac{25 \times 1 0 ^{- 3} V}{25 A}$
$= 0.001 Ω$