If the work function of a metal is 6.63 × 10-19 J, the maximum wavelength of the photon required to remove a photoelectron from the metal is nm. (Nearest integer) [Given: h=6.63 × 10-34 J s, and c =3 × 108 m s -1 ]

Question

If the work function of a metal is 6.63 × 10-19 J, the maximum wavelength of the photon required to remove a photoelectron from the metal is nm. (Nearest integer) [Given: h=6.63 × 10-34 J s, and c =3 × 108 m s -1 ] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

φ=6.63 × 10-19 J =( hc /λ)=(6.63 × 10-34 × 3 × 108/λ) ⇒ λ=3 × 10-7 m =300 nm

Q. If the work function of a metal is $6.63 \times 1 0^{- 19} J$ , the maximum wavelength of the photon required to remove a photoelectron from the metal is_____ $nm$ . (Nearest integer)
[Given : $h = 6.63 \times 1 0^{- 34} J s$ , and $c = 3 \times 1 0^{8} m s^{- 1}$ ]

$ϕ = 6.63 \times 1 0^{- 19} J = \frac{h c}{λ} = \frac{6.63 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{λ}$
$\Rightarrow λ = 3 \times 1 0^{- 7} m = 300 nm$

Q. If the work function of a metal is 6.63×10−19J, the maximum wavelength of the photon required to remove a photoelectron from the metal is_____ nm. (Nearest integer) [Given : h=6.63×10−34Js, and c=3×108ms−1 ]

ϕ=6.63×10−19J=λhc​=λ6.63×10−34×3×108​ ⇒λ=3×10−7m=300nm

Q. If the work function of a metal is $6.63 \times 1 0^{- 19} J$ , the maximum wavelength of the photon required to remove a photoelectron from the metal is_____ $nm$ . (Nearest integer)
[Given : $h = 6.63 \times 1 0^{- 34} J s$ , and $c = 3 \times 1 0^{8} m s^{- 1}$ ]

$ϕ = 6.63 \times 1 0^{- 19} J = \frac{h c}{λ} = \frac{6.63 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8}}{λ}$
$\Rightarrow λ = 3 \times 1 0^{- 7} m = 300 nm$