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Q. If the work function of a metal is $6.63 \times 10^{-19} J$, the maximum wavelength of the photon required to remove a photoelectron from the metal is_____ $nm$. (Nearest integer)
[Given : $h=6.63 \times 10^{-34} J s$, and $c =3 \times 10^{8} m s ^{-1}$ ]

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Solution:

$\phi=6.63 \times 10^{-19} J =\frac{ hc }{\lambda}=\frac{6.63 \times 10^{-34} \times 3 \times 10^{8}}{\lambda}$
$\Rightarrow \lambda=3 \times 10^{-7} m =300 \,nm$