A metal rod of uniform thickness ahd of length 1 m is suspended at its 25 cm division with help of a string. The rod remains horizontally straight when a block of mass 2 kg is suspended to the rod at its 10 cm division. The mass of rod is

Question

A metal rod of uniform thickness ahd of length 1 m is suspended at its 25 cm division with help of a string. The rod remains horizontally straight when a block of mass 2 kg is suspended to the rod at its 10 cm division. The mass of rod is (A) 0.4 kg (B) 0.8 kg (C) 1.2 kg (D) 1.6 kg

Tardigrade Admin · Accepted Answer

clockwise torque = anti clockwise torque mg × 25 = 2g × 15

Q. A metal rod of uniform thickness ahd of length 1 m is suspended at its 25 cm division with help of a string. The rod remains horizontally straight when a block of mass 2 kg is suspended to the rod at its 10 cm division. The mass of rod is

0.4 kg

0.8 kg

1.2 kg

1.6 kg

clockwise torque = anti clockwise torque
$m g \times 25 = 2 g \times 15$

Q. A metal rod of uniform thickness ahd of length 1 m is suspended at its 25 cm division with help of a string. The rod remains horizontally straight when a block of mass 2 kg is suspended to the rod at its 10 cm division. The mass of rod is

0.4 kg

0.8 kg

1.2 kg

1.6 kg

clockwise torque = anti clockwise torque mg×25=2g×15

clockwise torque = anti clockwise torque
$m g \times 25 = 2 g \times 15$