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  4. A metal rod of uniform thickness ahd of length 1 m is suspended at its 25 cm division with help of a string. The rod remains horizontally straight when a block of mass 2 kg is suspended to the rod at its 10 cm division. The mass of rod is

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Q. A metal rod of uniform thickness ahd of length 1 m is suspended at its 25 cm division with help of a string. The rod remains horizontally straight when a block of mass 2 kg is suspended to the rod at its 10 cm division. The mass of rod is

Solution:

clockwise torque = anti clockwise torque
$mg \times 25 = 2g \times 15 $

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