A metal has bcc structure and the edge length of its unit cell is 3.04 mathringA. The volume of the unit cell in cm3 will be

Question

A metal has bcc structure and the edge length of its unit cell is 3.04 mathringA. The volume of the unit cell in cm3 will be (A) 1.6 × 1021 cm3  (B) 2.81 × 10-23 cm3  (C) 6.02 × 10-23 cm3  (D) 6.6 × 10-24 cm3

Tardigrade Admin · Accepted Answer

Volume of unit cell (V) = a3 ∴ = (3.04 × 10-8 cm)3 = 2.81 × 10-23 cm3

Q. A metal has bcc structure and the edge length of its unit cell is $3.04 \overset{˚}{A}$ . The volume of the unit cell in $c m^{3}$ will be

$1.6 \times 1 0^{21} c m^{3}$

$2.81 \times 1 0^{- 23} c m^{3}$

$6.02 \times 1 0^{- 23} c m^{3}$

$6.6 \times 1 0^{- 24} c m^{3}$

Volume of unit cell (V) $= a^{3}$
$∴ = (3.04 \times 1 0^{- 8} c m)^{3}$
$= 2.81 \times 1 0^{- 23} c m^{3}$

Q. A metal has bcc structure and the edge length of its unit cell is 3.04A˚. The volume of the unit cell in cm3 will be

1.6×1021cm3

2.81×10−23cm3

6.02×10−23cm3

6.6×10−24cm3