Question

A metal has bcc structure and the edge length of its unit cell is $3.04\, \mathring{A}$. The volume of the unit cell in $cm^3$ will be

• A. $1.6 \times 10^{21} \, cm^3 $
• B. $2.81 \times 10^{-23 } \, cm^3 $
• C. $6.02 \times 10^{-23} \, cm^3 $
• D. $6.6 \times 10^{-24} \, cm^3 $

Answer 1

Answer: (B)

Volume of unit cell (V) $ = a^3$
$ \therefore \, \, = (3.04 \times 10^{-8} cm)^3$
$ = 2.81 \times 10^{-23} \, cm^3 $