When a lift accelerates upwards with uniform acceleration a ∴ Apparent weight of man R=m(g+a)
When a lift accelerates downwards with uniform acceleration a ∴ Apparent weight of man R=m(g−a)
When a lift descends freely ∴ Apparent weight of man R=m(g−g)=0
[since a=g]
When a lift is going down (without acceleration), ∴ Apparent weight of man R=m(g−0)=mg
[since a=0]
Hence, a man weigh more, when lift accelerates upwards