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Q. A man will weigh more when

UP CPMTUP CPMT 2007

Solution:

When a lift accelerates upwards with uniform acceleration a
$\therefore $ Apparent weight of man $R=m(g+a)$
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When a lift accelerates downwards with uniform acceleration a
$\therefore $ Apparent weight of man $R=m (g-a)$
image
When a lift descends freely
$\therefore $ Apparent weight of man $R=m(g-g)=0$
[since $a=g]$
When a lift is going down (without acceleration),
$\therefore $ Apparent weight of man $R=m(g-0)=mg$
[since $a=0]$
Hence, a man weigh more, when lift accelerates upwards