A man standing on the roof of a house of height h throws one particle vertically downwards and another particle horizontally with the same velocity u . The ratio of their velocities when they reach the earth's surface will be:

Question

A man standing on the roof of a house of height h throws one particle vertically downwards and another particle horizontally with the same velocity u . The ratio of their velocities when they reach the earth's surface will be: (A) √2 g h + u2:u (B) 1:2 (C) 1:1 (D) √2 g h + u2 :√2 g h

Tardigrade Admin · Accepted Answer

Velocity of A when it reaches the earth's surface =√u2 + 2 h g And velocity of B when it reaches the earth's surface =√u2 + 2 h g ∴ v1=v2

Q. A man standing on the roof of a house of height $h$ throws one particle vertically downwards and another particle horizontally with the same velocity $u$ . The ratio of their velocities when they reach the earth's surface will be:

$2 g h + u^{2} : u$

$1 : 2$

$1 : 1$

$2 g h + u^{2} : 2 g h$

Velocity of A when it reaches the earth's surface
$= u^{2} + 2 h g$
And velocity of B when it reaches the earth's surface
$= u^{2} + 2 h g$
$∴ v_{1} = v_{2}$

Q. A man standing on the roof of a house of height h throws one particle vertically downwards and another particle horizontally with the same velocity u . The ratio of their velocities when they reach the earth's surface will be:

2gh+u2​:u

1:2

1:1

2gh+u2​:2gh​