Q.
A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is 340ms−1, the distance between the cliffs is
Let the distance between the two cliffs be d. Since, the man is standing midway between the two cliffs, then the distance of man from either end is d/2.
The distance travelled by sound (in producing an echo) 2×2d=v×t ⇒d=340×1=340m