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  4. A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is 340 ms -1, the distance between the cliffs is

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Q. A man, standing between two cliffs, claps his hands and starts hearing a series of echoes at intervals of one second. If the speed of sound in air is $340\, ms ^{-1}$, the distance between the cliffs is

ManipalManipal 2012

Solution:

Let the distance between the two cliffs be $d$. Since, the man is standing midway between the two cliffs, then the distance of man from either end is $d / 2$.
The distance travelled by sound (in producing an echo)
$2 \times \frac{d}{2}=v \times t$
$\Rightarrow d=340 \times 1=340\, m$