A man M1 of mass 80 kg runs up a staircase in 15 s. Another man M2 also of mass 80 kg runs up the same staircase in 20 s. The ratio of the powers developed by them will be

Question

A man M1 of mass 80 kg runs up a staircase in 15 s. Another man M2 also of mass 80 kg runs up the same staircase in 20 s. The ratio of the powers developed by them will be (A) 1 (B) (4/3) (C) (16/9) (D) none of these

Tardigrade Admin · Accepted Answer

Power P=( text Work / text Time ) Work done by both will be same. Hence, (P1/P2)=(t2/t1)=(20/15)=(4/3)

Q. A man $M_{1}$ of mass $80 k g$ runs up a staircase in $15 s$ . Another man $M_{2}$ also of mass $80 k g$ runs up the same staircase in $20 s$ . The ratio of the powers developed by them will be

1

$\frac{4}{3}$

$\frac{16}{9}$

none of these

Power $P = \frac{Work}{Time}$
Work done by both will be same.
Hence, $\frac{P _{1}}{P _{2}} = \frac{t _{2}}{t _{1}} = \frac{20}{15} = \frac{4}{3}$

Q. A man M1​ of mass 80kg runs up a staircase in 15s. Another man M2​ also of mass 80kg runs up the same staircase in 20s. The ratio of the powers developed by them will be

1

34​

916​

none of these

Power P= Time Work ​ Work done by both will be same. Hence, P2​P1​​=t1​t2​​=1520​=34​

Q. A man $M_{1}$ of mass $80 k g$ runs up a staircase in $15 s$ . Another man $M_{2}$ also of mass $80 k g$ runs up the same staircase in $20 s$ . The ratio of the powers developed by them will be

$\frac{4}{3}$

$\frac{16}{9}$

Power $P = \frac{Work}{Time}$
Work done by both will be same.
Hence, $\frac{P _{1}}{P _{2}} = \frac{t _{2}}{t _{1}} = \frac{20}{15} = \frac{4}{3}$