A machine gun fires a bullet of mass 40 g with a velocity 1200 ms−1. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ?

Question

A machine gun fires a bullet of mass 40 g with a velocity 1200 ms−1. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ? (A) one (B) four (C) two (D) three

Tardigrade Admin · Accepted Answer

Change in momentum for each bullet fired is

= \frac{40}{1000} \times 1200 = 48 N

If a bullet fired exerts a force of

48 N

on man’s hand so

ρ

man can exert maximum force of

144 N

, number of bullets that can be fired

= 144/48 = 3

bullets.

Q. A machine gun fires a bullet of mass 40 g with a velocity 1200 ms−1. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ?

one

four

two

three

Change in momentum for each bullet fired is =100040​×1200=48N If a bullet fired exerts a force of 48N on man’s hand so ρ man can exert maximum force of 144N, number of bullets that can be fired =144/48=3 bullets.

Q. A machine gun fires a bullet of mass 40 g with a velocity 1200 $m s^{- 1}$ . The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ?

Change in momentum for each bullet fired is
$= \frac{40}{1000} \times 1200 = 48 N$
If a bullet fired exerts a force of $48 N$ on man’s hand so $ρ$ man can exert maximum force of $144 N$ , number of bullets that can be fired $= 144/48 = 3$ bullets.