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Q. A machine gun fires a bullet of mass 40 g with a velocity 1200 $ms^{−1}$. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can he fire per second at the most ?

AIEEEAIEEE 2004

Solution:

Change in momentum for each bullet fired is
$= \frac{40}{1000}\times1200 = 48\,N$
If a bullet fired exerts a force of $48\, N$ on man’s hand so $ρ$ man can exert maximum force of $144\, N$, number of bullets that can be fired $= 144/48 = 3$ bullets.