A loss free transformer has 500 turns on its primary winding and 2500 in secondary. The meters of the secondary indicate 200 volts at 8 amperes under these conditions. The voltage and current in the primary is

Question

A loss free transformer has 500 turns on its primary winding and 2500 in secondary. The meters of the secondary indicate 200 volts at 8 amperes under these conditions. The voltage and current in the primary is (A) 100 V , 16 A (B) 40 V , 40 A (C) 160 V , 10 A (D) 80 V , 20 A

Tardigrade Admin · Accepted Answer

(Vp/Vs)=(Np/Ns)=(500/2500)=(1/5) ⇒ Vp=(200/5)=40 V Also, ip Vp=is Vs ⇒ ip=is (Vs/Vp)=8 × 5=40 A

Q. A loss free transformer has $500$ turns on its primary winding and $2500$ in secondary. The meters of the secondary indicate $200$ volts at $8$ amperes under these conditions. The voltage and current in the primary is

100 V , 16 A

40 V , 40 A

160 V , 10 A

80 V , 20 A

$\frac{V _{p}}{V _{s}} = \frac{N _{p}}{N _{s}} = \frac{500}{2500} = \frac{1}{5}$
$\Rightarrow V_{p} = \frac{200}{5} = 40 V$
Also, $i_{p} V_{p} = i_{s} V_{s}$
$\Rightarrow i_{p} = i_{s} \frac{V _{s}}{V _{p}} = 8 \times 5 = 40 A$

Q. A loss free transformer has 500 turns on its primary winding and 2500 in secondary. The meters of the secondary indicate 200 volts at 8 amperes under these conditions. The voltage and current in the primary is