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Q. A loss free transformer has $500$ turns on its primary winding and $2500$ in secondary. The meters of the secondary indicate $200$ volts at $8$ amperes under these conditions. The voltage and current in the primary is

Electromagnetic Induction

Solution:

$\frac{V_{p}}{V_{s}}=\frac{N_{p}}{N_{s}}=\frac{500}{2500}=\frac{1}{5}$
$\Rightarrow V_{p}=\frac{200}{5}=40\, V$
Also, $i_{p} V_{p}=i_{s} V_{s}$
$\Rightarrow i_{p}=i_{s} \frac{V_{s}}{V_{p}}=8 \times 5=40\, A$