A long solenoid with 500 turns per unit length carries a current of 1.5 A. The magnetic induction at one of the ends of the solenoid on its axis is nearly

Question

A long solenoid with 500 turns per unit length carries a current of 1.5 A. The magnetic induction at one of the ends of the solenoid on its axis is nearly (A) 32 × 10-4T (B) 4 × 10-5T (C) 47 × 10-5T (D) 16 × 10-4T

Tardigrade Admin · Accepted Answer

B=(μ0 n i/2)=(4 π × 10-7 × 500 × 1.5/2)=47 × 10-5 J

Q. A long solenoid with $500$ turns per unit length carries a current of $1.5 A$ . The magnetic induction at one of the ends of the solenoid on its axis is nearly

$32 \times 1 0^{- 4}$ T

$4 \times 1 0^{- 5}$ T

$47 \times 1 0^{- 5}$ T

$16 \times 1 0^{- 4}$ T

$8 \times 1 0^{- 5}$ T

$B = \frac{μ _{0} ni}{2} = \frac{4 π \times 1 0 ^{- 7} \times 500 \times 1.5}{2} = 47 \times 1 0^{- 5} J$

Q. A long solenoid with 500 turns per unit length carries a current of 1.5A. The magnetic induction at one of the ends of the solenoid on its axis is nearly

32×10−4T

4×10−5T

47×10−5T

16×10−4T

8×10−5T

B=2μ0​ni​=24π×10−7×500×1.5​=47×10−5J