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Q. A long solenoid with $500$ turns per unit length carries a current of $1.5 \,A$. The magnetic induction at one of the ends of the solenoid on its axis is nearly

KEAMKEAM 2020

Solution:

$B=\frac{\mu_{0} \,n i}{2}=\frac{4 \pi \times 10^{-7} \times 500 \times 1.5}{2}=47 \times 10^{-5} \,J$