A long solenoid is formed by winding 20 turns / cm. The current necessary to produce a magnetic field of 20 millitesla inside the solenoid will be approximately ((μ0/4 π)=10-7. tesla - metre/ampere )

Question

A long solenoid is formed by winding 20 turns / cm. The current necessary to produce a magnetic field of 20 millitesla inside the solenoid will be approximately ((μ0/4 π)=10-7. tesla - metre/ampere ) (A) 8.0 A (B) 4.0 A (C) 2.0 A (D) 1.0 A

Tardigrade Admin · Accepted Answer

B =μ0 n i ⇒ i=(B/μ0 n) =(20 × 10-3/4 π × 10-7 × 20 × 100)=7.9 A =8 A

Q. A long solenoid is formed by winding $20$ turns $/ c m$ . The current necessary to produce a magnetic field of $20$ millitesla inside the solenoid will be approximately $(\frac{μ _{0}}{4 π} = 1 0^{- 7}$ tesla - metre/ampere $)$

$8.0 A$

$4.0 A$

$2.0 A$

$1.0 A$

$B = μ_{0} ni$
$\Rightarrow i = \frac{B}{μ _{0} n}$
$= \frac{20 \times 1 0 ^{- 3}}{4 π \times 1 0 ^{- 7} \times 20 \times 100} = 7.9 A = 8 A$

Q. A long solenoid is formed by winding 20 turns /cm. The current necessary to produce a magnetic field of 20 millitesla inside the solenoid will be approximately (4πμ0​​=10−7 tesla - metre/ampere )

8.0A

4.0A

2.0A

1.0A