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  4. A long solenoid is formed by winding 20 turns / cm. The current necessary to produce a magnetic field of 20 millitesla inside the solenoid will be approximately ((μ0/4 π)=10-7. tesla - metre/ampere )

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Q. A long solenoid is formed by winding $20$ turns $/ cm$. The current necessary to produce a magnetic field of $20$ millitesla inside the solenoid will be approximately $\left(\frac{\mu_0}{4 \pi}=10^{-7}\right.$ tesla - metre/ampere $)$

Moving Charges and Magnetism

Solution:

$ B =\mu_0 n i $
$\Rightarrow i=\frac{B}{\mu_0 n} $
$=\frac{20 \times 10^{-3}}{4 \pi \times 10^{-7} \times 20 \times 100}=7.9 A =8 A$