A long solenoid has n turns per meter and current 1 A is flowing through it. The magnetic field at the ends of the solenoid is

Question

A long solenoid has n turns per meter and current 1 A is flowing through it. The magnetic field at the ends of the solenoid is (A) (μ0 nI /2) (B) μ0 nI (C) Zero (D) 2 μ0 nI

Tardigrade Admin · Accepted Answer

Magnetic field at the ends of solenoid is half of the field present inside. B text end =(B text inside /2) B prime=(μ o nI /2)

Q. A long solenoid has n turns per meter and current $1 A$ is flowing through it. The magnetic field at the ends of the solenoid is

$\frac{μ _{0} n I}{2}$

$μ_{0} n I$

Zero

$2 μ_{0} n I$

Magnetic field at the ends of solenoid is half of the field present inside.
$B_{end} = \frac{B _{inside}}{2}$
$B^{'} = \frac{μ _{o} n I}{2}$

Q. A long solenoid has n turns per meter and current 1A is flowing through it. The magnetic field at the ends of the solenoid is

2μ0​nI​

μ0​nI