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Q. A long solenoid has n turns per meter and current $1 A$ is flowing through it. The magnetic field at the ends of the solenoid is

Moving Charges and Magnetism

Solution:

Magnetic field at the ends of solenoid is half of the field present inside.
$B_{\text {end }}=\frac{B_{\text {inside }}}{2}$
$B ^{\prime}=\frac{\mu_{ o } nI }{2}$