A long solenoid has 500 turns, When a current of 2 A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 × 10-3 Wb, then self induction of the solenoid is

Question

A long solenoid has 500 turns, When a current of 2 A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4 × 10-3 Wb, then self induction of the solenoid is (A) 2.0 henry (B) 1.0 henry (C) 4.0 henry (D) 2.5 henry

Tardigrade Admin · Accepted Answer

φ=500 × 4 × 10-3=2 Wb Li = N φ L =(2/2)=1 H

Q. A long solenoid has $500$ turns, When a current of $2 A$ is passed through it, the resulting magnetic flux linked with each turn of the solenoid is $4 \times 1 0^{- 3} Wb$ , then self induction of the solenoid is

$2.0$ henry

$1.0$ henry

$4.0$ henry

$2.5$ henry

$ϕ = 500 \times 4 \times 1 0^{- 3} = 2 Wb$
$L i = Nϕ$
$L = \frac{2}{2} = 1 H$

Q. A long solenoid has 500 turns, When a current of 2A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×10−3Wb, then self induction of the solenoid is

2.0 henry

1.0 henry

4.0 henry

2.5 henry