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Q. A long solenoid has 500 turns, When a current of 2A is passed through it, the resulting magnetic flux linked with each turn of the solenoid is 4×103Wb, then self induction of the solenoid is

KCETKCET 2022Electromagnetic Induction

Solution:

ϕ=500×4×103=2Wb
Li=Nϕ
L=22=1H