A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the cell is placed in 0.05 MBaCl 2 solution at 300 K ?

Question

A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the cell is placed in 0.05 MBaCl 2 solution at 300 K ? (A) 1.23 atm (B) 6.15 atm (C) 3.69 atm (D) None of these

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/chemistry/fb16461c07d8d20b0797d4222b3335e6-.png" /> π =( iC 2- C 1 i ) RT =(0.2-0.05 × 3) × 0.0821 × 300 =(0.2)-0.15) × 0.0821 × 300 =0.05 × 0.0821 × 300 =1.23 atm

Q. A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the cell is placed in $0.05 MB a C l_{2}$ solution at $300 K ?$

1.23 atm

6.15 atm

3.69 atm

None of these

$π = (i C_{2} - C_{1} i) RT$

$= (0.2 - 0.05 \times 3) \times 0.0821 \times 300$

$= (0.2) - 0.15) \times 0.0821 \times 300$

$= 0.05 \times 0.0821 \times 300$

$= 1.23 a t m$

Q. A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the cell is placed in 0.05MBaCl2​ solution at 300K?