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Q. A living cell contains a solution which is isotonic with 0.2 M glucose solution. What osmotic pressure develops when the cell is placed in $0.05 MBaCl _{2}$ solution at $300\, K ?$

Solutions

Solution:

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$\pi =\left( iC _{2}- C _{1} i \right) RT$

$=(0.2-0.05 \times 3) \times 0.0821 \times 300$

$=(0.2)-0.15) \times 0.0821 \times 300$

$=0.05 \times 0.0821 \times 300$

$=1.23\, atm$