A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at its sides. If the radius of the vessel is 0.05 m and the speed of rotation is 2 rev s- 1 , the difference in the height of liquid at the centre of the vessel and its sides is

Question

A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at its sides. If the radius of the vessel is 0.05 m and the speed of rotation is 2 rev s- 1 , the difference in the height of liquid at the centre of the vessel and its sides is (A) 0.001 textm (B) 0.002 text m (C) 0.01 text m (D) 0.02 text m

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-li3spkx4utpcwq3c.jpg" /> h=(r2 ω 2/2 g) h=((0.05)2 (2 × 2 π )2/2 × g) =0.02 m

Q. A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at its sides. If the radius of the vessel is $0.05 m$ and the speed of rotation is $2 re v s^{- 1}$ , the difference in the height of liquid at the centre of the vessel and its sides is

$0.001 m$

$0.002 m$

$0.01 m$

$0.02 m$

$h = \frac{r ^{2} ω ^{2}}{2 g}$
$h = \frac{( 0.05 ) ^{2} ( 2 \times 2 π ) ^{2}}{2 \times g}$
$= 0.02 m$

Q. A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at its sides. If the radius of the vessel is 0.05m and the speed of rotation is 2revs−1 , the difference in the height of liquid at the centre of the vessel and its sides is

0.001m

0.002 m

0.01 m

0.02 m