Question

A liquid is kept in a cylindrical vessel which is rotated along its axis. The liquid rises at its sides. If the radius of the vessel is $0.05 \, m$ and the speed of rotation is $2 \, rev \, s^{- 1}$ , the difference in the height of liquid at the centre of the vessel and its sides is

• A. $0.001 \, \text{m}$
• B. $0.002 \text{ m}$
• C. $0.01 \text{ m}$
• D. $0.02 \text{ m}$

Answer 1

Answer: (D)

$h=\frac{r^{2} \omega ^{2}}{2 \, g}$
$h=\frac{\left(0.05\right)^{2} \, \left(2 \times 2 \pi \right)^{2}}{2 \times g}$
$=0.02 \, m$