A liquid at 30°C is poured very slowly into a Calorimeter that is at temperature of 110°C. The boiling temperature of the liquid is 80°C. It is found that the first 5 gm of the liquid completely evaporates. After pouring another 80 gm of the liquid the equilibrium temperature is found to be 50°C. The ratio of the Latent heat of the liquid to its specific heat will be °C. [Neglect the heat exchange with surrounding]

Question

A liquid at 30°C is poured very slowly into a Calorimeter that is at temperature of 110°C. The boiling temperature of the liquid is 80°C. It is found that the first 5 gm of the liquid completely evaporates. After pouring another 80 gm of the liquid the equilibrium temperature is found to be 50°C. The ratio of the Latent heat of the liquid to its specific heat will be °C. [Neglect the heat exchange with surrounding] (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Case-I 5C Ã 50 + 5 L = C2 Ã 30...(1) Case-II 80 C [50-30] = C2 [80-50] ...(2) By equation (1) (2) 1600 C = 250 C + 5L ∴ (L/C)=(1350/5)=270°C

Case-I 5C×50+5L=C2​×30...(1) Case-II 80C[50−30]=C2​ [80-50] ...(2) By equation (1) & (2) 1600C=250C+5L ∴CL​=51350​=270∘C

Case-I $5 C \times 50 + 5 L = C_{2} \times 30$ ...(1)
Case-II $80 C [50 - 30] = C_{2}$ [80-50] ...(2)
By equation (1) & (2)
$1600 C = 250 C + 5 L$
$∴ \frac{L}{C} = \frac{1350}{5} = 27 0^{\circ} C$