1. Tardigrade
  2. Question
  3. Physics
  4. A liquid at 30°C is poured very slowly into a Calorimeter that is at temperature of 110°C. The boiling temperature of the liquid is 80°C. It is found that the first 5 gm of the liquid completely evaporates. After pouring another 80 gm of the liquid the equilibrium temperature is found to be 50°C. The ratio of the Latent heat of the liquid to its specific heat will be °C. [Neglect the heat exchange with surrounding]

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Q. A liquid at $30^{\circ}C$ is poured very slowly into a Calorimeter that is at temperature of $110^{\circ}C$. The boiling temperature of the liquid is $80^{\circ}C$. It is found that the first 5 gm of the liquid completely evaporates. After pouring another 80 gm of the liquid the equilibrium temperature is found to be $50^{\circ}C$. The ratio of the Latent heat of the liquid to its specific heat will be_______ $^{\circ}C$.
[Neglect the heat exchange with surrounding]

JEE AdvancedJEE Advanced 2019

Solution:

Case-I $5C × 50 + 5 L = C_2 × 30$...(1)
Case-II $80 \,C [50-30] = C_2$ [80-50] ...(2)
By equation (1) & (2)
$1600\, C = 250\, C + 5L$
$\therefore \frac{L}{C}=\frac{1350}{5}=270^{\circ}C$