A lead bullet hits a steel plate with a velocity 400 m / s. If the impact is perfectly inclastic and heat produced is equally shared between the bullet and the target then the rise in temperature of bullet is (specific heat capacity of lead =125 J kg -1 K -1 )

Question

A lead bullet hits a steel plate with a velocity 400 m / s. If the impact is perfectly inclastic and heat produced is equally shared between the bullet and the target then the rise in temperature of bullet is (specific heat capacity of lead =125 J kg -1 K -1 ) (A) 320° C (B) 321° C (C) 221° C (D) 210° C

Tardigrade Admin · Accepted Answer

If produced heat equally shared then half of it shared between the two ms Δ T =(1/2)((1/2) mv 2) Δ T =( v 2/ s × 4)=(400 × 400/125 × 4) =320° C

Q. A lead bullet hits a steel plate with a velocity $400 m / s$ . If the impact is perfectly inclastic and heat produced is equally shared between the bullet and the target then the rise in temperature of bullet is (specific heat capacity of lead $= 125 J k g^{- 1} K^{- 1}$ )

$32 0^{\circ} C$

$32 1^{\circ} C$

$22 1^{\circ} C$

$21 0^{\circ} C$

If produced heat equally shared then half of it shared between the two
$m s Δ T = \frac{1}{2} (\frac{1}{2} m v^{2})$
$Δ T = \frac{v ^{2}}{s \times 4} = \frac{400 \times 400}{125 \times 4}$
$= 32 0^{\circ} C$

Q. A lead bullet hits a steel plate with a velocity 400m/s. If the impact is perfectly inclastic and heat produced is equally shared between the bullet and the target then the rise in temperature of bullet is (specific heat capacity of lead =125Jkg−1K−1 )

320∘C

321∘C

221∘C

210∘C