A layer of benzene (μ1=1.5) 6 cm deep floats on water (μ2=1.33) 4 cm deep. When viewed vertically through air the apparent distance (in cm ) of the bottom of the vessel below the surface of the benzene will be ?

Question

A layer of benzene (μ1=1.5) 6 cm deep floats on water (μ2=1.33) 4 cm deep. When viewed vertically through air the apparent distance (in cm ) of the bottom of the vessel below the surface of the benzene will be ? (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/352f46a591e760a967f1960ebd1af0ac-.png" /> Image of bottom after refraction at benzene water surface is formed at =((4/4 / 3))(1.5) =4.5 cm below benzene water surface Now for refraction at benzene air surface, this acts as object and final image is formed at =((10.5/1.5))(1)=7 cm below benzene-air surface.

Q. A layer of benzene $(μ_{1} = 1.5) 6 c m$ deep floats on water $(μ_{2} = 1.33) 4 c m$ deep. When viewed vertically through air the apparent distance (in $c m$ ) of the bottom of the vessel below the surface of the benzene will be ?

Image of bottom after refraction at benzene water surface is formed at
$= (\frac{4}{4/3}) (1.5)$
$= 4.5 c m$ below benzene water surface Now for refraction at benzene air surface, this acts as object and final image is formed at
$= (\frac{10.5}{1.5}) (1) = 7 c m$ below benzene-air surface.

Q. A layer of benzene (μ1​=1.5)6cm deep floats on water (μ2​=1.33)4cm deep. When viewed vertically through air the apparent distance (in cm ) of the bottom of the vessel below the surface of the benzene will be ?

Image of bottom after refraction at benzene water surface is formed at =(4/34​)(1.5) =4.5cm below benzene water surface Now for refraction at benzene air surface, this acts as object and final image is formed at =(1.510.5​)(1)=7cm below benzene-air surface.

Q. A layer of benzene $(μ_{1} = 1.5) 6 c m$ deep floats on water $(μ_{2} = 1.33) 4 c m$ deep. When viewed vertically through air the apparent distance (in $c m$ ) of the bottom of the vessel below the surface of the benzene will be ?

Image of bottom after refraction at benzene water surface is formed at
$= (\frac{4}{4/3}) (1.5)$
$= 4.5 c m$ below benzene water surface Now for refraction at benzene air surface, this acts as object and final image is formed at
$= (\frac{10.5}{1.5}) (1) = 7 c m$ below benzene-air surface.