Q.
A=⎣⎡l1l2l3m1m2m3n1n2n3⎦⎤andB=⎣⎡p1p2p3q1q2q3r1r2r3⎦⎤ where pi,qi,ri are the co-factors of the elements li,mi,ni for i=1,2,3. If (l1,m1,n1),(l2,m2,n2) and (l3,m3,n3) are the direction cosines of three mutually perpendicular lines then (p1,q1,r1),(p2,q2,r2) and (p3,q3,r3) are
Let a=l1i^+m1j^+n1k^,b=l2i^+m2j^+n2k^ and c=l3i^+m3j^+n3k^
Given that a,b,c are three mutually perpendicular unit vectors.
Then p1i^+q1j^+r1k^=b×c=a (∵b×c parallel to a and b×c,a are unit vectors)
Similarly, p2i^+q2j^+r2k^=c×a=b
and p3i^+q3j^+r3k^=a×b=c
These vectors are also mutually perpendicular unit vectors