A hydrocarbon A (C4H8) on reaction with HCl gives a compound B (C4H9Cl) which on reaction with 1 mole of NH3 gives a compound C (C4H11N). On reacting with NaNO2 and HCl followed by treatment with water, compound C yields an optically active alcohol, D. Ozonolysis of A gives 2 moles of acetaldehyde. The structure of compound C is

Question

A hydrocarbon A (C4H8) on reaction with HCl gives a compound B (C4H9Cl) which on reaction with 1 mole of NH3 gives a compound C (C4H11N). On reacting with NaNO2 and HCl followed by treatment with water, compound C yields an optically active alcohol, D. Ozonolysis of A gives 2 moles of acetaldehyde. The structure of compound C is (A) 2-aminobutane (B) N,N-dimethylethanamine (C) diethylamine (D) butylamine

Tardigrade Admin · Accepted Answer

On ozonolysis A gives 2 moles of acetaldehyde, so A is CH3CH = CHCH3 The reactions are as follows

$2$ -aminobutane

$N, N$ -dimethylethanamine

diethylamine

butylamine

On ozonolysis A gives $2$ moles of acetaldehyde, so $A$ is $C H_{3} C H = C H C H_{3}$
The reactions are as follows

2-aminobutane

N,N-dimethylethanamine

diethylamine

butylamine

On ozonolysis A gives 2 moles of acetaldehyde, so A is CH3​CH=CHCH3​ The reactions are as follows

$2$ -aminobutane

$N, N$ -dimethylethanamine

On ozonolysis A gives $2$ moles of acetaldehyde, so $A$ is $C H_{3} C H = C H C H_{3}$
The reactions are as follows