1. Tardigrade
  2. Question
  3. Chemistry
  4. A hydrocarbon A (C4H8) on reaction with HCl gives a compound B (C4H9Cl) which on reaction with 1 mole of NH3 gives a compound C (C4H11N). On reacting with NaNO2 and HCl followed by treatment with water, compound C yields an optically active alcohol, D. Ozonolysis of A gives 2 moles of acetaldehyde. The structure of compound C is

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A hydrocarbon $A (C_4H_8)$ on reaction with $HCl$ gives a compound $B (C_4H_9Cl)$ which on reaction with $1$ mole of $NH_3$ gives a compound $C (C_4H_{11}N)$. On reacting with $NaNO_2$ and $HCl$ followed by treatment with water, compound $C$ yields an optically active alcohol, $D$. Ozonolysis of A gives $2$ moles of acetaldehyde. The structure of compound $C$ is

Amines

Solution:

On ozonolysis A gives $2$ moles of acetaldehyde, so $A$ is $CH_3CH = CHCH_3$
The reactions are as follows

Solution Image