A hose lying on the ground shoots a stream of water upward at an angle of 60° to the horizontal with a velocity of 16 m s -1. The height at which the water strikes the wall 8 m away is

Question

A hose lying on the ground shoots a stream of water upward at an angle of 60° to the horizontal with a velocity of 16 m s -1. The height at which the water strikes the wall 8 m away is (A) 8.96 m (B) 10.96 m (C) 12.96 m (D) 6.96 m

Tardigrade Admin · Accepted Answer

uH=16 cos 60°=16 × (1/2)=8 m s -1 Time taken to reach the wall =(8/8)=1 s Now, uV=16 sin 60°=16 × (√3/2)=8 √3 m s -1 ∴ h=8 √3 × 1-(1/2) × 9,8 × 12 =13.86-4.9=8.96 m

Q. A hose lying on the ground shoots a stream of water upward at an angle of $6 0^{\circ}$ to the horizontal with a velocity of $16 m s^{- 1}$ . The height at which the water strikes the wall 8 m away is

8.96 m

10.96 m

12.96 m

6.96 m

$u_{H} = 16 cos 6 0^{\circ} = 16 \times \frac{1}{2} = 8 m s^{- 1}$
Time taken to reach the wall $= \frac{8}{8} = 1 s$
Now, $u_{V} = 16 sin 6 0^{\circ} = 16 \times \frac{3}{2} = 83 m s^{- 1}$
$∴ h = 83 \times 1 - \frac{1}{2} \times 9, 8 \times 1^{2}$
$= 13.86 - 4.9 = 8.96 m$

Q. A hose lying on the ground shoots a stream of water upward at an angle of 60∘ to the horizontal with a velocity of 16ms−1. The height at which the water strikes the wall 8 m away is