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Q. A hose lying on the ground shoots a stream of water upward at an angle of $60^{\circ}$ to the horizontal with a velocity of $16 \,m\, s ^{-1}$. The height at which the water strikes the wall 8 m away is

Motion in a Plane

Solution:

$u_{H}=16 \cos 60^{\circ}=16 \times \frac{1}{2}=8 \,m \,s ^{-1}$
Time taken to reach the wall $=\frac{8}{8}=1 \,s$
Now, $u_{V}=16 \sin 60^{\circ}=16 \times \frac{\sqrt{3}}{2}=8 \sqrt{3} m s ^{-1}$
$\therefore h=8 \sqrt{3} \times 1-\frac{1}{2} \times 9,8 \times 1^{2}$
$=13.86-4.9=8.96 \,m$