A horizontal force F is applied to a frictionless pulley of mass m2. The horizontal surface is smooth. The acceleration of the block of mass m1 is n times the acceleration of the pulley. The value of n is

Question

A horizontal force F is applied to a frictionless pulley of mass m2. The horizontal surface is smooth. The acceleration of the block of mass m1 is n times the acceleration of the pulley. The value of n is (A) 1 (B) 2 (C) 3 (D) 4

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/51117e5cd54585aeb21ab53f4fca6f5c-.png" /> T δ x1-2 T δ x2=0 ⇒ (δ2 x1/d t2)=(2 δ2 x2/d t2) or a1=2 a2 If a1=n ⋅ a2 ⇒ n=2

Q. A horizontal force $F$ is applied to a frictionless pulley of mass $m_{2}$ . The horizontal surface is smooth. The acceleration of the block of mass $m_{1}$ is $n$ times the acceleration of the pulley. The value of $n$ is

1

2

3

4

$T δ x_{1} - 2 T δ x_{2} = 0$
$\Rightarrow \frac{δ ^{2} x _{1}}{d t ^{2}} = \frac{2 δ ^{2} x _{2}}{d t ^{2}}$ or $a_{1} = 2 a_{2}$
If $a_{1} = n \cdot a_{2} \Rightarrow n = 2$

Q. A horizontal force F is applied to a frictionless pulley of mass m2​. The horizontal surface is smooth. The acceleration of the block of mass m1​ is n times the acceleration of the pulley. The value of n is

1

2

3

4

Tδx1​−2Tδx2​=0 ⇒dt2δ2x1​​=dt22δ2x2​​ or a1​=2a2​ If a1​=n⋅a2​⇒n=2

Q. A horizontal force $F$ is applied to a frictionless pulley of mass $m_{2}$ . The horizontal surface is smooth. The acceleration of the block of mass $m_{1}$ is $n$ times the acceleration of the pulley. The value of $n$ is

$T δ x_{1} - 2 T δ x_{2} = 0$
$\Rightarrow \frac{δ ^{2} x _{1}}{d t ^{2}} = \frac{2 δ ^{2} x _{2}}{d t ^{2}}$ or $a_{1} = 2 a_{2}$
If $a_{1} = n \cdot a_{2} \Rightarrow n = 2$