A hemispherical surface of radius R is placed in a uniform electric field of intensity E parallel to the axis of its circular plane. What will be the electric flux φ through the hemispherical surface

Question

A hemispherical surface of radius R is placed in a uniform electric field of intensity E parallel to the axis of its circular plane. What will be the electric flux φ through the hemispherical surface (A) 2 π R E (B) 2 π R2 E (C) π R2 E (D) (4 / 3) π R3 E

Tardigrade Admin · Accepted Answer

φe=0 φc s+φh s=0 -π R2 E+φh s=0 ⇒ φh s=π R2 E

Q. A hemispherical surface of radius $R$ is placed in a uniform electric field of intensity $E$ parallel to the axis of its circular plane. What will be the electric flux $ϕ$ through the hemispherical surface

$2 π RE$

$2 π R^{2} E$

$π R^{2} E$

$(4/3) π R^{3} E$

$ϕ_{e} = 0$
$ϕ_{cs} + ϕ_{h s} = 0$
$- π R^{2} E + ϕ_{h s} = 0$
$\Rightarrow ϕ_{h s} = π R^{2} E$

Q. A hemispherical surface of radius R is placed in a uniform electric field of intensity E parallel to the axis of its circular plane. What will be the electric flux ϕ through the hemispherical surface

2πRE

2πR2E

πR2E

(4/3)πR3E