A helicopter is flying horizontally at an altitude of 2 km with a speed of 100 ms- 1 . A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is (.g=10 ms- 2.)

Question

A helicopter is flying horizontally at an altitude of 2 km with a speed of 100 ms- 1 . A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is (.g=10 ms- 2.) (A) 2 km (B) 0.2 km (C) 20 km (D) 4 km

Tardigrade Admin · Accepted Answer

t = √( text2h/ textg) = √((2) ( text2000)/ text10) = text20 sec x = ( text100) ( text20) = text2 km

Q. A helicopter is flying horizontally at an altitude of 2 km with a speed of $100 m s^{- 1}$ . A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is $(g = 10 m s^{- 2})$

2 km

0.2 km

20 km

4 km

$t = \frac{2h}{g} = \frac{( 2 ) ( 2000 )}{10} = 20 sec$
$x = (100) (20) = 2 km$

Q. A helicopter is flying horizontally at an altitude of 2 km with a speed of 100ms−1 . A packet is dropped from it. The horizontal distance between the point where the packet is dropped and the point where it hits the ground is (g=10ms−2)