A heavy nucleus having mass number 200 gets disintegrated into two small fragments of mass number 80 and 120 . If binding energy per nucleon for parent atom is 6.5 MeV and for daughter nuclei is 7 MeV and 8 MeV respectively, then the energy released in the decay is X × 110 MeV. Find the value of X

Question

A heavy nucleus having mass number 200 gets disintegrated into two small fragments of mass number 80 and 120 . If binding energy per nucleon for parent atom is 6.5 MeV and for daughter nuclei is 7 MeV and 8 MeV respectively, then the energy released in the decay is X × 110 MeV. Find the value of X (A) 3 (B) 4 (C) 2 (D) 1

Tardigrade Admin · Accepted Answer

Energy released =(80 × 7+120 × 8-200 × 6.5) =( text total power /( text energy ) text fission )=(5/200 × 1.6 × 10-13)=1.56 × 1011 s -1

Q. A heavy nucleus having mass number 200 gets disintegrated into two small fragments of mass number 80 and 120 . If binding energy per nucleon for parent atom is 6.5MeV and for daughter nuclei is 7MeV and 8MeV respectively, then the energy released in the decay is X×110MeV. Find the value of X

3

4

2

1

Energy released =(80×7+120×8−200×6.5) = fission energy ​ total power ​=200×1.6×10−135​=1.56×1011s−1

Energy released $= (80 \times 7 + 120 \times 8 - 200 \times 6.5)$
$= \frac{total power}{\frac{energy}{fission}} = \frac{5}{200 \times 1.6 \times 1 0 ^{- 13}} = 1.56 \times 1 0^{11} s^{- 1}$