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Q. A heavy nucleus having mass number $200$ gets disintegrated into two small fragments of mass number $80$ and $120$ . If binding energy per nucleon for parent atom is $6.5 \,MeV$ and for daughter nuclei is $7\, MeV$ and $8 \,MeV$ respectively, then the energy released in the decay is $X \times 110\, MeV$. Find the value of $X$

Nuclei

Solution:

Energy released $=(80 \times 7+120 \times 8-200 \times 6.5) $
$=\frac{\text { total power }}{\frac{\text { energy }}{\text { fission }}}=\frac{5}{200 \times 1.6 \times 10^{-13}}=1.56 \times 10^{11} \,s ^{-1}$