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Tardigrade
Question
Chemistry
(a) H2 O2 + O3 arrow H2O + 2O2 (b) H2 O2 + Ag2O arrow 2Ag + H2O + O2 Role of hydrogen peroxide in the above reactions is respectively -
Q. (a)
H
2
O
2
+
O
3
→
H
2
O
+
2
O
2
(b)
H
2
O
2
+
A
g
2
O
→
2
A
g
+
H
2
O
+
O
2
Role of hydrogen peroxide in the above reactions is respectively -
4230
233
AIPMT
AIPMT 2014
Redox Reactions
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A
Oxidizing in (a) and reducing in (b)
21%
B
Reducing in (a) and oxidizing in (b)
10%
C
Reducing in (a) and (b)
49%
D
Oxidizing in (a) and (b)
19%
Solution:
(a)
H
2
O
2
+
O
3
→
H
2
O
+
2
O
2
In this reaction,
O
3
is reduced into
O
−
2
ion.
(b)
H
2
O
2
+
A
g
2
O
→
2
A
g
+
H
2
O
+
O
2
In this reaction,
A
g
2
O
is reduced to
A
g
.
Hence,
H
2
O
2
acts as reducing agent in both the reactions.