Question

A graph plotted between ${\text{t}}_{\frac{1}{2}}$ vs. log concentration is a straight line. What conclusion can you draw from the given graph

• A. $n=1,t_{\frac{1}{2}}=\frac{1}{k.a}$
• B. $n=2,t_{\frac{1}{2}}=\frac{1}{a}$
• C. $n=1,t_{\frac{1}{2}}=\frac{0.693}{k}$
• D. none of these

Answer 1

Answer: (C)

$t_{\frac{1}{2}}\alpha a^{1-n}$

or $t_{\frac{1}{2}}=k{a}^{1-n}$

$log{t}_{\frac{1}{2}}=logk+\left(1-n\right)loga$

so slope $=1-n$

or $1-n=0$

or $n=1$