Question

A graph plotted between $\text{t}_{\frac{1}{2}}$ vs. log concentration is a straight line. What conclusion can you draw from the given graph

• A. $n=1,t_{\frac{1}{2}}=\frac{1}{k . a}$
• B. $n=2,t_{\frac{1}{2}}=\frac{1}{a}$
• C. $n=1,t_{\frac{1}{2}}=\frac{0.693}{k}$
• D. none of these

Answer 1

Answer: (C)

$t_{\frac{1}{2}}\alpha a^{1 - n}$

or $t_{\frac{1}{2}}=ka^{1 - n}$

$log t_{\frac{1}{2}}=log ⁡ k+\left(1 - n\right)log ⁡ a$

so slope $=1-n$

or $1-n=0$

or $n=1$