Question

A graph plotted between log $t_{50\%}$ vs. log concentration is a straight line. What conclusion can you draw from the given graph

• A. $n=1,t_{1/2}=\frac{0.693}{k}$
• B. $n=2,t_{1/2}=\frac{1}{a}$
• C. $n=1,t_{1/2}=\frac{1}{k.a}$
• D. none of these

Answer 1

Answer: (A)

$t_{1/2}\alpha a^{1-n}$
or $t_{1/2}=k{a}^{1-n}$
$log{t}_{1/2}=logk+(1-n)loga$
so slope $=1-n$
or $1-n=0$
or $n=1$