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Q. A graph plotted between log $t_{50 \%}$ vs. log concentration is a straight line. What conclusion can you draw from the given graph
Question

NTA AbhyasNTA Abhyas 2022

Solution:

$t_{1 / 2}\alpha a^{1 - n}$
or $t_{1 / 2}=ka^{1 - n}$
$logt_{1 / 2}=logk+\left(\right.1-n\left.\right)loga$
so slope $=1-n$
or $1-n=0$
or $n=1$